Hi Jason, welcome on board. Good to see you are already planning an upgrade
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| system critique please http://byap.backyardmagazines.com/forum/viewtopic.php?f=1&t=2198 |
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| Author: | mrgrackletx [ Oct 8th, '07, 04:37 ] |
| Post subject: | system critique please |
Hiya, my name's Jason and I'm new to this aquaponics forum. I've got a small system set up right now.. a 55 gallon barrel with two gold fish in there, the water is pumped out into a couple of pvp pipes that then run back into the barrel... very simple. Now that I have this small system running I want to upgrade just a bit. I'm about to start building a 300 gallon tank and I was going to hook up 150 gallons worth of growing medium to filter the water. I know it's nota 4x2x1 ratio but I figure if I go for lower stocking density it shouldnt be a problem... right? I was thinking I'd be alright up to .25lbs per 2 gallons of water instead of the 1lb per 2 gallons, sound reasonable? Next question... I'm pumping the water out of the 300 gallon tank with a 500 gph pump.. I think it should be running at 450 gph at the head I'm going to have it pump up to. I'm pumping it out of the tank into 6 grow beds that are made from 55 gallons barrels cut sideways, so about 150 gallons of grow bed. I was going to have these all set up as seperate eb-flow beds using an autosiphon on each one. So... here's my main question... the water comes out of the pump through a 1" pipe and then I want to divert it into 6 seperate lines/hoses/whatever to feed into the grow beds... what sized pipe/hose should I use to make sure that whatever gets 'equal' distribution to all the grow beds? I was going to have the pump pump up to the 3' head I need then go into a 2" pipe to use as a manafold and then have all 6 hoses/pipe branch off at approximately the same spot... but what sized pipe/hose should I use? Thanks for the read. Jason |
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| Author: | Valduare [ Oct 8th, '07, 04:42 ] |
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should be a divide math problem right? |
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| Author: | creative1 [ Oct 8th, '07, 04:56 ] |
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forget the manifold to a degree you will need to have a valve on each to regulate the flow to each GB |
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| Author: | Jaymie [ Oct 8th, '07, 05:27 ] |
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Hi Jason, welcome on board. Good to see you are already planning an upgrade
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| Author: | tamo42 [ Oct 8th, '07, 06:56 ] |
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Never one to turn down a math problem.... A(1in) = 1/4*pi in^2 So you need to divide that by 6. So each outlet pipe should have an area of 1/24*pi in^2. 1/24 = r^2; r ~= 0.2; diameter ~= .38. Closest English measurement would be 3/8" diameter. You'll probably still need valves due to imperfections in exit height and turbulence in the T's and such. |
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| Author: | mrgrackletx [ Oct 8th, '07, 08:01 ] |
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not to sound to dense here but could you explain the equation? A(1in) = 1/4*pi in ^2 i know finding the area of a circle is pi*radius^2, I'm not sure what you're doing with the 1/4... Thanks 
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| Author: | RupertofOZ [ Oct 8th, '07, 08:56 ] | ||
| Post subject: | Re: system critique please | ||
Welcome Jason..... don't know about the maths.... EB overcame a similar design problem by utilising a header tank/manifold as below...... Then as suggested you can utilise ball valve taps on each distribution line to equalize the flow... This way you can also use cheap 19mm (3/4") irrigation tubing....
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| Author: | steve [ Oct 8th, '07, 15:23 ] |
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i'd go with thamos solution, makes sense to me. If you have issues then insert valves into each of the six legs and tweak. |
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| Author: | EllKayBee [ Oct 8th, '07, 17:43 ] |
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Quote: A(1in) = 1/4*pi in ^2
i know finding the area of a circle is pi*radius^2, I'm not sure what you're doing with the 1/4... or Area = pi*diameter ^2 /4 (the pipe sizes are the diameter measurements) |
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| Author: | creative1 [ Oct 8th, '07, 21:30 ] |
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You've still got it Les! |
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| Author: | mrgrackletx [ Oct 8th, '07, 22:25 ] |
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Ah ... so... area of a 1" pipe would be .785" .... 3.14 * (1/2)^2 = 0.785 square inches 0.785/6 = 0.138 square inches. so... 0.138 = pi*r^2 pi * .0138 = r^2 0.0417 = r^2 .2 = r .4 = diameter thanks for the math lesson
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| Author: | tamo42 [ Oct 9th, '07, 02:43 ] |
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No problem
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